# How do you solve #4p<32#?

##### 1 Answer

Mar 28, 2017

#### Explanation:

We are solving for

#(cancel(4)p)/cancel4<32/4#

#p<(4*8)/4#

#p<(cancel(4)*8)/cancel4#

#p<8#

Mar 28, 2017

We are solving for

#(cancel(4)p)/cancel4<32/4#

#p<(4*8)/4#

#p<(cancel(4)*8)/cancel4#

#p<8#

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